<div dir="ltr"><div><p class="MsoNormal" style="margin:0in 0in 0.0001pt;line-height:normal;font-size:11pt;font-family:Calibri,"sans-serif""><span style="font-size:12pt;font-family:Arial,"sans-serif";background-image:initial;background-position:initial;background-size:initial;background-repeat:initial;background-origin:initial;background-clip:initial"> </span><span style="font-size:12pt;font-family:"Times New Roman","serif";background-image:initial;background-position:initial;background-size:initial;background-repeat:initial;background-origin:initial;background-clip:initial">Dear a</span><span style="font-family:"Times New Roman","serif";font-size:12pt">ll </span><span style="font-family:"Times New Roman","serif";font-size:12pt">GSAS-II experts </span></p><p class="MsoNormal" style="margin:0in 0in 0.0001pt;line-height:normal;font-size:11pt;font-family:Calibri,"sans-serif""><span style="font-size:12pt;font-family:"Times New Roman","serif""></span></p>
<span style="font-size:12pt;line-height:115%;font-family:"Times New Roman","serif"">I am trying to calculate
crystallite size and Microstrain for Lead Oxide(PbO). As you Know</span> ; <span style="font-size:12pt;font-family:"Times New Roman","serif";color:rgb(17,17,17);background-image:initial;background-position:initial;background-size:initial;background-repeat:initial;background-origin:initial;background-clip:initial">GSAS-II
computes the crystallite sizes (</span><span style="font-size:12pt;font-family:"Times New Roman","serif""><span id="gmail-_x0000_t75"> </span></span><span style="font-family:"Times New Roman","serif";font-size:12pt">10</span><sup style="font-family:"Times New Roman","serif"">-6</sup><span style="font-size:12pt;font-family:"Times New Roman","serif"">m)<span style="color:rgb(17,17,17);background-image:initial;background-position:initial;background-size:initial;background-repeat:initial;background-origin:initial;background-clip:initial"> in
three different (isotropic, uniaxial and ellipsoidal) Microstrain</span></span><span style="background-image:initial;background-position:initial;background-size:initial;background-repeat:initial;background-origin:initial;background-clip:initial;font-size:12pt;font-family:"Times New Roman","serif";color:black"> in terms of the amount of lattice spread</span><span style="background-image:initial;background-position:initial;background-size:initial;background-repeat:initial;background-origin:initial;background-clip:initial;font-size:13.5pt;font-family:"Segoe UI","sans-serif";color:rgb(68,68,68)">, </span><span style="font-size:12pt;font-family:"Times New Roman","serif"">unitless
fraction of Δd/d (or equivalently ΔQ/Q) times 10<sup>6</sup><span style="color:rgb(17,17,17);background-image:initial;background-position:initial;background-size:initial;background-repeat:initial;background-origin:initial;background-clip:initial"> (isotropic, uniaxial and generalized)
arrangement. Below is my refinement result. The average size is very large and there is no microstrain like this.</span></span></div><div><span style="font-size:12pt;font-family:"Times New Roman","serif""><span style="color:rgb(17,17,17);background-image:initial;background-position:initial;background-size:initial;background-repeat:initial;background-origin:initial;background-clip:initial"> Is there anyone who can clarify this problem please?</span></span></div><div><span style="font-size:12pt;font-family:"Times New Roman","serif""><span style="color:rgb(17,17,17);background-image:initial;background-position:initial;background-size:initial;background-repeat:initial;background-origin:initial;background-clip:initial"><br></span></span></div><div> Average size
<span style="font-family:"Times New Roman","serif";font-size:12pt">10</span><sup style="font-family:"Times New Roman","serif"">-6</sup>m Average Microstrain (
<span style="font-family:"Times New Roman","serif";font-size:16px">10</span><sup style="font-family:"Times New Roman","serif"">6</sup>m)<br>Isotropic Uniaxial Ellipsoidal Isotropic Uniaxial Generalized <br> 0.01 1.541 0.926 2231 8800 7489<br></div><div>I am waiting for your best answer</div><div>Thanks!</div></div>